(2x-5)^2+5x(x-4)=(3x+2)(3x-2)-11

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Solution for (2x-5)^2+5x(x-4)=(3x+2)(3x-2)-11 equation: 



(2x-5)^2+5x(x-4)=(3x+2)(3x-2)-11

We move all terms to the left:

(2x-5)^2+5x(x-4)-((3x+2)(3x-2)-11)=0

We use the square of the difference formula

9x^2+(2x-5)^2+5x(x-4)+4=0

We multiply parentheses

9x^2+5x^2+(2x-5)^2-20x+4=0

We add all the numbers together, and all the variables

14x^2-20x+(2x-5)^2+4=0

We move all terms containing x to the left, all other terms to the right

14x^2-20x+(2x-5)^2=-4

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